Wednesday, February 17, 2010

Snooker Balls Problems The Problem Of The Snooker Balls With Three Weighs Only To Discover The Odd One Out And, Two Answers Given.?

The problem of the snooker balls with three weighs only to discover the odd one out and, two answers given.? - snooker balls problems

a) Assume that) when a weight of 6 to 6, take the lighter 6 and weigh up to 3-3 (second cradle, etc.

b) It is assumed that if we have 6 wieghs against 6, Take 6, and despite the biggest 3) to 3 (second cradles, etc.

But what if you divide the lightest six (3 to 3) and balance!

In contrast, B, which is when the couple split 6 (3 to 3) and balance!

A storm was so heavy, three, and now weighs six balls (A) and the balls heavier (B), light
Ball to discover the strange!

Thank you for your efforts, though.

1 comments:

drgnrave said...

http://www.ridaalbarazi.com/blog/2007/03 ...
Jazz, I only mention this:
Jazz says ..

The number of balls 1-12. Weigh 1, 2, 3 a.m. to 4 p.m. to 5, 6, 7 and 8
If (1, 2, 3, 4) and (5, 6, 7, 8) Balance:
Weighing, 9 and 10 to 11, 8 (known as the 8 ball is odd).
If (9, 10) and (11, 8) balance: 12, if odd.

Weigh 12 against another, whether heavy or light.

If (9, 10) and (11, 8) Non-equilibrium: Suppose that 11 a.m. to 8 p.m. are heavier
9 a.m. to 10 p.m., then either 11 is heavy, light or 9 or 10, the light is.

Weigh 9 against 10, if the remaining 11 is difficult, and if they do,
the lighter from 9 a.m. to 10 p.m., the odd ball.

(Story Similarly, if there are 11 a.m. to 8 p.m. lighter than the 9 a.m. to 10 p.m.).

If (1, 2, 34) and (5, 6, 7, 8) Non-equilibrium
Let's say, 5, 6, 7 a.m. to 8 p.m. are heavier than the 1, 2, 3 and 4 Then: one of
(1, 2, 3 or 4) is the light, or a (5, 6, 7 or 8) is cumbersome.
Weigh 1, 2 and 5-3, 6 and 9
If the balance is so difficult, or 7 or 8 is heavy or 4 is light.
Weigh 7 against 8, when the ratio, 4 is the odd ball, otherwise the
from 7 a.m. to 8 p.m. serious is the odd ball.

If (1, 2, 5) and (3, 6, 9) is not balanced, let 1, 2 a.m. to 5 p.m. are easier
3, 6 a.m. to 9 p.m., then 6 is either difficult or easy is 1 or 2, the light is.
Weigh 1 against 2 to find out which of the three possibilities come true.
Otherwise, let 1, 2 a.m. to 5 p.m. are heavier than the 3, 6 a.m. to 9 p.m., then 3
is the light, or 5 is hard.

Weigh 3 against (say)2 For which of the two possibilities.

(Similar argument if 1, 2 a.m. to 5 p.m. are lighter than the 3, 6 a.m. to 9 p.m.).

I think it is correct.

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