**The problem of the snooker balls with three weighs only to discover the odd one out and, two answers given.? - snooker balls problems**

a) Assume that) when a weight of 6 to 6, take the lighter 6 and weigh up to 3-3 (second cradle, etc.

b) It is assumed that if we have 6 wieghs against 6, Take 6, and despite the biggest 3) to 3 (second cradles, etc.

But what if you divide the lightest six (3 to 3) and balance!

In contrast, B, which is when the couple split 6 (3 to 3) and balance!

A storm was so heavy, three, and now weighs six balls (A) and the balls heavier (B), light

Ball to discover the strange!

Thank you for your efforts, though.

## Wednesday, February 17, 2010

### Snooker Balls Problems The Problem Of The Snooker Balls With Three Weighs Only To Discover The Odd One Out And, Two Answers Given.?

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## 1 comments:

http://www.ridaalbarazi.com/blog/2007/03 ...

Jazz, I only mention this:

Jazz says ..

The number of balls 1-12. Weigh 1, 2, 3 a.m. to 4 p.m. to 5, 6, 7 and 8

If (1, 2, 3, 4) and (5, 6, 7, 8) Balance:

Weighing, 9 and 10 to 11, 8 (known as the 8 ball is odd).

If (9, 10) and (11, 8) balance: 12, if odd.

Weigh 12 against another, whether heavy or light.

If (9, 10) and (11, 8) Non-equilibrium: Suppose that 11 a.m. to 8 p.m. are heavier

9 a.m. to 10 p.m., then either 11 is heavy, light or 9 or 10, the light is.

Weigh 9 against 10, if the remaining 11 is difficult, and if they do,

the lighter from 9 a.m. to 10 p.m., the odd ball.

(Story Similarly, if there are 11 a.m. to 8 p.m. lighter than the 9 a.m. to 10 p.m.).

If (1, 2, 34) and (5, 6, 7, 8) Non-equilibrium

Let's say, 5, 6, 7 a.m. to 8 p.m. are heavier than the 1, 2, 3 and 4 Then: one of

(1, 2, 3 or 4) is the light, or a (5, 6, 7 or 8) is cumbersome.

Weigh 1, 2 and 5-3, 6 and 9

If the balance is so difficult, or 7 or 8 is heavy or 4 is light.

Weigh 7 against 8, when the ratio, 4 is the odd ball, otherwise the

from 7 a.m. to 8 p.m. serious is the odd ball.

If (1, 2, 5) and (3, 6, 9) is not balanced, let 1, 2 a.m. to 5 p.m. are easier

3, 6 a.m. to 9 p.m., then 6 is either difficult or easy is 1 or 2, the light is.

Weigh 1 against 2 to find out which of the three possibilities come true.

Otherwise, let 1, 2 a.m. to 5 p.m. are heavier than the 3, 6 a.m. to 9 p.m., then 3

is the light, or 5 is hard.

Weigh 3 against (say)2 For which of the two possibilities.

(Similar argument if 1, 2 a.m. to 5 p.m. are lighter than the 3, 6 a.m. to 9 p.m.).

I think it is correct.

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